Jump to folder in path

Scripting Forums AppleScript | Mac OS X
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#1

I need an applescript that will ask for a Job number and then open a specific folder based on that number.

If I type 12345, the folder I need it to open is /Volumes/Jobs\ Archive/123/12345
My problem is in grabbing and passing the first 3 characters into the folder path - it errors out.
I think I’m really close, can anybody tell me where my problem is at?

Thanks

Here’s the code:

set the_job_number to text returned of (display dialog "Job number?" default answer "00000")
set the_prefix to characters 1 through 3 of the_job_number
tell application "Finder"
	activate
	open folder the_job_number of folder the_prefix of disk "Jobs Archive"
end tell

Once it functions, I may like to add a couple enhancements. Like, if I don’t enter a 5 digit number, dispaly a dialog. If the volume “Jobs Archive” (it’s not really a disk, is that a problem?) isn’t mounted, mount it from afp://server/Jobs Archive. But I have to get it to function first!

#2

Hi Bigmac

I think you need to do abit of coercion:
this line

set the_prefix to characters 1 through 3 of the_job_number

is returning a list it needs to be a string

set the_prefix to characters 1 through 3 of the_job_number as string

hope i’m right and this helps

#3

“Characters” will return a list, not text.

You should just get text in the first place.

set the_job_number to text returned of (display dialog "Job number?" default answer "00000")
set the_prefix to text 1 through 3 of the_job_number
#4

Doh!

cheers Bruce

#5

Shweet! Thanks for the fast reply.
It worked great!