Mathematical syntax...

sbriss · February 6, 2014, 2:27pm

Hi everybody, I need to figure out how to use the right syntax to do that:

tell application "Adobe Acrobat Pro"
		
		open theFile
		
		set PageCount to (count of every page)
		set PageCountINDD to ((count of every page) / 4)

I need to the answer of (PageCoundINDD) to increase to the next integer who’s dividable by 8.

Can somebody help me please?

Yvan_Koenig · February 6, 2014, 5:15pm

Maybe this may help :

set PageCountINDD to PageCount div 4
repeat
	if PageCountINDD / 8 = PageCountINDD div 8 then exit repeat
	set PageCountINDD to PageCountINDD + 1
end repeat
PageCountINDD

Yvan KOENIG (VALLAURIS, France) jeudi 6 fÃ©vrier 2014 18:15:52

haolesurferdude · February 6, 2014, 5:24pm

Here is one way of accomplishing your page math problem that assumes the pdf document of interest is open in Acrobat.

tell application "Adobe Acrobat Pro"
	activate
	set PageCount to the number of pages of the active doc
	set PageCountINDD to (PageCount / 4)
end tell

Nigel_Garvey · February 6, 2014, 5:29pm

Hi.

(PageCountNDD + 8) div 8 * 8

Marc_Anthony · February 6, 2014, 6:22pm

Hi. Your intent is unclear. Let’s say you have a 19 page document… Nigel’s approach would give you 24 as a result, which is divisible by 8, but isn’t within your existing page range. If you want to just advance by 8, you could do:

tell application "Adobe Acrobat Pro"
	repeat with whatever from ((count pages) div 4) to count pages by 8
		whatever--{4,12}
	end
end

Yvan_Koenig · February 6, 2014, 6:46pm

It seems that you read wrongly Nigel code.

With a 19 pages document Nigel’s code returns PageCountNDD = 8

Yvan KOENIG (VALLAURIS, France) jeudi 6 fÃ©vrier 2014 19:46:32

Nigel_Garvey · February 6, 2014, 6:52pm

Hi Yvan.

My code returns the next multiple of 8 up from whatever PageCountNDD is at that moment.

sbriss · February 6, 2014, 7:05pm

Sorry I didn’t explain myself well and made a mistake!

It’s the PageCount of my PDF that need to be dividable by 8. So if it’s not, I will add blank pages to reach that number.

StefanK · February 6, 2014, 7:22pm

not an one-liner, but this solution does not add anything if the number of pages is dividable by 8


set PageCountINDD to numberOfPages() -- pseudo handler for application specific code
set modulo to PageCountINDD mod 8
if modulo is not 0 then
	set PageCountINDD to PageCountINDD + 8 - modulo
end if

PS: I’m using this in Acrobat for a brochure print (dividable by 4) to add empty pages


             repeat while ((count pages of mainDoc) mod 4 is not 0)
                    tell mainDoc to insert pages after (count pages of mainDoc) from emptyPageDoc number of pages 1 starting with 1
                end repeat

Yvan_Koenig · February 6, 2014, 8:26pm

It’s what I was trying to point.
Maybe I was not clear enough.

With a document of 19 pages, the initial value of PageCountNDD is 19/4 = 4.75
So your code returns 8.

I was just responding to Marc Anthony who wrote that your code was returning 24.

Here is StephanK 's algorithm as a one liner :

tell PageCountINDD mod 8 to if it is not 0 then set PageCountINDD to PageCountINDD + 8 - it

Nigel_Garvey · February 6, 2014, 9:59pm

Stefan’s method’s more suitable than mine for the purpose decribed in post #8, since it doesn’t raise numbers which are already multiples of 8. Yvan’s successfully one-lined it, but it can also be done mathematically like this:

PageCountINDD + (8 - PageCountINDD mod 8) mod 8

Yvan_Koenig · February 7, 2014, 10:05am

In Nigel’s code, the variable PageCountNDD was not supposed to be the count of every pages but the result of

(count of every pages pages) / 4