Please let me know the way to click a button of the popup menu

Scripting Forums AppleScript | Mac OS X
#1

I’m trying to make a new service on the network

So I found the way to click “add new service” with below source code


tell application "System Preferences"
	activate
	set the current pane to pane id "com.apple.preference.network"
end tell

tell application "System Events"
	tell process "System Preferences"
		click button 5 of window 1
	end tell
end tell

but I can find the way to click list menu and the button of popup menu…

please help me…

#2

the parent element of the popup menu is a sheet.
Try this


property newServiceKind : "Ethernet"

tell application "System Preferences"
	activate
	set the current pane to pane id "com.apple.preference.network"
end tell

tell application "System Events"
	tell process "System Preferences"
		tell window 1
			click button 5
			repeat until exists sheet 1
				delay 0.2
			end repeat
			tell sheet 1
				tell pop up button 1
					click
					pick menu item newServiceKind of menu 1
					repeat until its value is newServiceKind
						delay 0.2
					end repeat
				end tell
				set value of text field 1 to "new ethernet service"
				click button "Create"
			end tell
		end tell
	end tell
end tell
#3

I appreciate your help^^

I worked with your code

thanks again!