Hi - I’m brand new to applescript and uncertain if I can use applescript to solve following problem:
I want to open an executable file (*.osx - made with Director) & parse a parameter to this application using applescript?
Unfortunately I did’t find a solution jet - I just can run the application, but can’t parse any parameters?
My script so far:
tell application "Finder"
activate
select file "index.osx" of folder "test" of disk "CDR"
open selection
end tell
If there isn’t a way - what 'd you suggest doing? I’m trying to avoid having 50 different executable starter-files - each one would be about 5 MB - Which takes too much space on a CDR… Compiled Applescripts are much smaller…
Thanks for any suggestions!
Wommi
Thanks Martin - but unfortunately I can’t make it working - I’m not sure what I’m doing wrong because I’m brand new to this…
So I think it might help to describe what I was doing:
I was trying to run the script in the “Script Editor” using the “Run”-button - To limit the chances of errors I’ve taken out all paths:
set filepath to "/index.osx"
do shell script "open " & quoted form of filepath & " -size 500x600"
As result I’m getting a pop-up by the Script-Editor - it seems like AppleScript doesn’t allow me to add any parameters?:
I was trying another way too:
set filepath to "index.osx"
set para to " -hallo"
do shell script "open " & quoted form of filepath & quoted form of para
Yes it does - but it doesn’t matter if I’m using the full path or not - it doesn’t even start the script because of those error messages…
The code doesn’t seem to be valid?
PS: I’m using
ScriptEditor Version 2.2 (2.2)
AppleScript 2.0
If the «open» command does not work for you, then you can also try to execute the application/script directly (make sure its permissions are set to 755):
set filepath to "/Volumes/CDR/test/index.osx"
set para to "-hallo"
do shell script quoted form of filepath & space & quoted form of para
For example, I just wrote a small Python script named test.py containing the following code:
[i]
#!/usr/bin/python
import sys
print sys.argv[1]
[/i]
The script’s permissions are set to 755 and it is located on my desktop. The following code works for me:
set filepath to POSIX path of (((path to desktop) as Unicode text) & "test.py")
set para to "Yeah"
set shellresult to do shell script quoted form of filepath & space & quoted form of para
display dialog shellresult
Hi Martin
I think we are getting there… There are still some obstacles to take.
Good news:
The script gets compiled now! Don’t know why the “open” shell command doesn’t work for me…
set filepath to "/Volumes/CDR/test/index.osx"
set para to "-hallo"
do shell script quoted form of filepath & space & quoted form of para
I set the permissions to 755 in the terminal
and checked it:
So it seems it should work now… When I run the applescript-application-file it comes up with the following:
“Press Run to run this script, or Quit to quit.” - It’s like in Windows
And when I press run it comes up with:
“sh: /index.osx: Permission denied”
Then I thought it could help to chmod the index.osx too - but it didn’t help:
“Press Run to run this script, or Quit to quit.” - Not again!
“sh: /index.osx: cannot execute binary file”
any ideas?
I’ll try this Python script later… and have a coffee now
Cheers for the help so far!
There is no need to change the permissions of the AppleScript application itself, it’s already executable when saved with Script Editor. But of course you need to make sure that your *.osx file is executable (chmod755).
Nevertheless you will run into problems when the *.osx file is not executable at all (on Mac OS X). You can easily test this by simply dragging the *.osx file into a Terminal window, then hit Return. If it won’t run from there, it also won’t run using the «do shell script» command.
There are still some obstacles to take.